مبرهنة لوكاس

لمعلومات عن the theorem in complex analysis، انظر Gauss–Lucas theorem.

في نظرية الأعداد، مبرهنة لوكاس Lucas's theorem تعبر عن remainder of division of the binomial coefficient ${\tbinom {m}{n}}$ by a prime number p in terms of the base p expansions of the integers m and n.

Lucas's theorem first appeared in 1878 in papers by Édouard Lucas.

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 نص المبرهنة

For non-negative integers m and n and a prime p, the following congruence relation holds:

${\binom {m}{n}}\equiv \prod _{i=0}^{k}{\binom {m_{i}}{n_{i}}}{\pmod {p}},$

حيث

$m=m_{k}p^{k}+m_{k-1}p^{k-1}+\cdots +m_{1}p+m_{0},$

و

$n=n_{k}p^{k}+n_{k-1}p^{k-1}+\cdots +n_{1}p+n_{0}$

are the base p expansions of m and n respectively. This uses the convention that ${\tbinom {m}{n}}=0$ if m < n.

البراهين

There are several ways to prove Lucas's theorem.

Combinatorial proof

Let M be a set with m elements, and divide it into m_i cycles of length pⁱ for the various values of i. Then each of these cycles can be rotated separately, so that a group G which is the Cartesian product of cyclic groups C_pⁱ acts on M. It thus also acts on subsets N of size n. Since the number of elements in G is a power of p, the same is true of any of its orbits. Thus in order to compute ${\tbinom {m}{n}}$ modulo p, we only need to consider fixed points of this group action. The fixed points are those subsets N that are a union of some of the cycles. More precisely one can show by induction on k-i, that N must have exactly n_i cycles of size pⁱ. Thus the number of choices for N is exactly $\prod _{i=0}^{k}{\binom {m_{i}}{n_{i}}}{\pmod {p}}$.

Proof based on generating functions

This proof is due to Nathan Fine.

If p is a prime and n is an integer with 1 ≤ n ≤ p − 1, then the numerator of the binomial coefficient

${\binom {p}{n}}={\frac {p\cdot (p-1)\cdots (p-n+1)}{n\cdot (n-1)\cdots 1}}$

is divisible by p but the denominator is not. Hence p divides ${\tbinom {p}{n}}$. In terms of ordinary generating functions, this means that

$(1+X)^{p}\equiv 1+X^{p}{\pmod {p}}.$

Continuing by induction, we have for every nonnegative integer i that

$(1+X)^{p^{i}}\equiv 1+X^{p^{i}}{\pmod {p}}.$

Now let m be a nonnegative integer, and let p be a prime. Write m in base p, so that $m=\sum _{i=0}^{k}m_{i}p^{i}$ for some nonnegative integer k and integers m_i with 0 ≤ m_i ≤ p-1. Then

${\begin{aligned}\sum _{n=0}^{m}{\binom {m}{n}}X^{n}&=(1+X)^{m}=\prod _{i=0}^{k}\left((1+X)^{p^{i}}\right)^{m_{i}}\\&\equiv \prod _{i=0}^{k}\left(1+X^{p^{i}}\right)^{m_{i}}=\prod _{i=0}^{k}\left(\sum _{n_{i}=0}^{m_{i}}{\binom {m_{i}}{n_{i}}}X^{n_{i}p^{i}}\right)\\&=\prod _{i=0}^{k}\left(\sum _{n_{i}=0}^{p-1}{\binom {m_{i}}{n_{i}}}X^{n_{i}p^{i}}\right)=\sum _{n=0}^{m}\left(\prod _{i=0}^{k}{\binom {m_{i}}{n_{i}}}\right)X^{n}{\pmod {p}},\end{aligned}}$

where in the final product, n_i is the ith digit in the base p representation of n. This proves Lucas's theorem.

 النتائج

• A binomial coefficient ${\tbinom {m}{n}}$ is divisible by a prime p if and only if at least one of the base p digits of n is greater than the corresponding digit of m.
• In particular, ${\tbinom {m}{n}}$ is odd if and only if the binary digits (bits) in the binary expansion of n are a subset of the bits of m.

 التقلبات والتعميمات

• Kummer's theorem asserts that the largest integer k such that p^k divides the binomial coefficient ${\tbinom {m}{n}}$ (or in other words, the valuation of the binomial coefficient with respect to the prime p) is equal to the number of carries that occur when n and m − n are added in the base p.

• Generalizations of Lucas's theorem to the case of p being a prime power are given by Davis and Webb (1990) and Granville (1997).

• The q-Lucas theorem is a generalization for the q-binomial coefficients, first proved by J. Désarménien.

 وصلات خارجية

• قالب:PlanetMath
• A. Laugier; M. P. Saikia (2012). "A new proof of Lucas' Theorem" (PDF). Notes on Number Theory and Discrete Mathematics. 18 (4): 1–6. arXiv:1301.4250.
• R. Meštrović (2014). "Lucas' theorem: its generalizations, extensions and applications (1878–2014)". arXiv:1409.3820 [math.NT].